ArrayObject::offsetExists

    (PHP 5, PHP 7, PHP 8)

    ArrayObject::offsetExists — Returns whether the requested index exists

    Description

    public ArrayObject::offsetExists(mixed $key): bool

    Parameters

    key

    The index being checked.

    Return Values

    true if the requested index exists, otherwise false

    Examples

    Example #1 ArrayObject::offsetExists() example

    <?php
    $arrayobj     = new ArrayObject(array('zero', 'one', 'example'=>'e.g.'));
    var_dump($arrayobj->offsetExists(1));
    var_dump($arrayobj->offsetExists('example'));
    var_dump($arrayobj->offsetExists('notfound'));
    ?>

    The above example will output:

    bool(true)
bool(true)
bool(false)

    Improve This Page

    Learn How To Improve This Page • Submit a Pull Request • Report a Bug
    ＋add a note

    User Contributed Notes 1 note

    up
    2
    goran at extensionsforjoomla dot com
    17 years ago
    In versions prior to PHP 5.2.2 offsetExists() would return false if index value is null.
    <?php
    // running PHP 5.2.1
    $params = new ArrayObject(array('INT'=>null, 'STR'=> null, 'BOOL'=>null, 'LOB'=>null));
    $test = $params->offsetExists('INT');
    var_dump($test);
    // result would be bool(false)
    // running PHP 5.2.2
    $params = new ArrayObject(array('INT'=>null, 'STR'=> null, 'BOOL'=>null, 'LOB'=>null));
    $test = $params->offsetExists('INT');
    var_dump($test);
    // result would be bool(true)
    ?>
    Both tests where made on Windows platform.
    ＋add a note
    To Top